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2003-2-12 · For the proof, we will count the number of dots in T(n) but, instead of summing the numbers 1, 2, 3, etc up to n we will find the total using only one multiplication and one division!. To do this, we will fit two copies of a triangle of dots together, one red and an upside-down copy in green. E.g. T(4)=1+2+3+4 + =
Get Price2010-9-14 · Little ant said: 1^2 + 2^2 + 3^2 + ... + 2^n = 2^ (n-1) This makes absolutely no sense. I mean, look at it for a second... firstly you failed to notice the pattern correctly since 2^n means 2^1+2^2+2^3 instead of what is shown. And secondly, how can that all equal 2^ (n-1) when on the left side of the equation, you already have 2^n which means ...
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Get PriceYinOYang 1.2 is available as a stand-alone software package, with the same functionality as the service above. Ready-to-ship packages exist for the most common UNIX platforms. There is a download page for academic users; other users are requested to contact CBS Software Package Manager at [email protected]
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